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81x^2+99x+28=0
a = 81; b = 99; c = +28;
Δ = b2-4ac
Δ = 992-4·81·28
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-27}{2*81}=\frac{-126}{162} =-7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+27}{2*81}=\frac{-72}{162} =-4/9 $
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